b^2+14b-95=0

Solution for b^2+14b-95=0 equation:

Simplifying
b2 + 14b + -95 = 0

Reorder the terms:
-95 + 14b + b2 = 0

Solving
-95 + 14b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-19 + -1b)(5 + -1b) = 0

Subproblem 1
Set the factor '(-19 + -1b)' equal to zero and attempt to solve:

Simplifying
-19 + -1b = 0

Solving
-19 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '19' to each side of the equation.
-19 + 19 + -1b = 0 + 19

Combine like terms: -19 + 19 = 0
0 + -1b = 0 + 19
-1b = 0 + 19

Combine like terms: 0 + 19 = 19
-1b = 19

Divide each side by '-1'.
b = -19

Simplifying
b = -19
Subproblem 2
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Solution
b = {-19, 5}